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      Distance from Petersburg to Sint-Genesius-Rode

      The shortest distance (air line) between Petersburg and Sint-Genesius-Rode is 3,957.18 mi (6,368.47 km).

      How far is Petersburg from Sint-Genesius-Rode

      Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 21:55 (04.02.2025)

      Sint-Genesius-Rode is located in Arr. Halle-Vilvoorde, Belgium within 50° 44' 42" N 4° 20' 47.04" E (50.7450, 4.3464) coordinates. The local time in Sint-Genesius-Rode is 03:55 (05.02.2025)

      The calculated flying distance from Sint-Genesius-Rode to Sint-Genesius-Rode is 3,957.18 miles which is equal to 6,368.47 km.

      Petersburg, Virginia, United States

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      Sint-Genesius-Rode, Arr. Halle-Vilvoorde, Belgium

      Related Distances to Sint-Genesius-Rode