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      Distance from Petersburg to Sobral de Monte Agraco

      The shortest distance (air line) between Petersburg and Sobral de Monte Agraco is 3,620.76 mi (5,827.06 km).

      How far is Petersburg from Sobral de Monte Agraco

      Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 00:04 (06.03.2025)

      Sobral de Monte Agraco is located in Oeste, Portugal within 39° 1' 4.8" N -10° 50' 52.8" W (39.0180, -9.1520) coordinates. The local time in Sobral de Monte Agraco is 05:04 (06.03.2025)

      The calculated flying distance from Sobral de Monte Agraco to Sobral de Monte Agraco is 3,620.76 miles which is equal to 5,827.06 km.

      Petersburg, Virginia, United States

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      Sobral de Monte Agraco, Oeste, Portugal

      Related Distances to Sobral de Monte Agraco