Distance from Petersburg to Steenbergen
The shortest distance (air line) between Petersburg and Steenbergen is 3,933.29 mi (6,330.02 km).
How far is Petersburg from Steenbergen
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 10:58 (01.03.2025)
Steenbergen is located in West-Noord-Brabant, Netherlands within 51° 34' 59.88" N 4° 15' 0" E (51.5833, 4.2500) coordinates. The local time in Steenbergen is 16:58 (01.03.2025)
The calculated flying distance from Steenbergen to Steenbergen is 3,933.29 miles which is equal to 6,330.02 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Steenbergen, West-Noord-Brabant, Netherlands