Distance from Petersburg to Steenokkerzeel
The shortest distance (air line) between Petersburg and Steenokkerzeel is 3,959.60 mi (6,372.37 km).
How far is Petersburg from Steenokkerzeel
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 23:55 (04.02.2025)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 05:55 (05.02.2025)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 3,959.60 miles which is equal to 6,372.37 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium