Distance from Petersburg to Sulzbach-Rosenberg
The shortest distance (air line) between Petersburg and Sulzbach-Rosenberg is 4,292.45 mi (6,908.03 km).
How far is Petersburg from Sulzbach-Rosenberg
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 20:43 (18.02.2025)
Sulzbach-Rosenberg is located in Amberg-Sulzbach, Germany within 49° 30' 0" N 11° 45' 0" E (49.5000, 11.7500) coordinates. The local time in Sulzbach-Rosenberg is 02:43 (19.02.2025)
The calculated flying distance from Sulzbach-Rosenberg to Sulzbach-Rosenberg is 4,292.45 miles which is equal to 6,908.03 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Sulzbach-Rosenberg, Amberg-Sulzbach, Germany