Distance from Petersburg to Veenendaal
The shortest distance (air line) between Petersburg and Veenendaal is 3,975.10 mi (6,397.31 km).
How far is Petersburg from Veenendaal
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 11:25 (01.03.2025)
Veenendaal is located in Utrecht, Netherlands within 52° 1' 0.12" N 5° 32' 60" E (52.0167, 5.5500) coordinates. The local time in Veenendaal is 17:25 (01.03.2025)
The calculated flying distance from Veenendaal to Veenendaal is 3,975.10 miles which is equal to 6,397.31 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Veenendaal, Utrecht, Netherlands