Distance from Petersburg to Vetraz-Monthoux
The shortest distance (air line) between Petersburg and Vetraz-Monthoux is 4,158.08 mi (6,691.78 km).
How far is Petersburg from Vetraz-Monthoux
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 17:11 (12.02.2025)
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 23:11 (12.02.2025)
The calculated flying distance from Vetraz-Monthoux to Vetraz-Monthoux is 4,158.08 miles which is equal to 6,691.78 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Vetraz-Monthoux, Haute-Savoie, France