Distance from Petersburg to Waldshut-Tiengen
The shortest distance (air line) between Petersburg and Waldshut-Tiengen is 4,201.10 mi (6,761.01 km).
How far is Petersburg from Waldshut-Tiengen
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 16:08 (12.12.2025)
Waldshut-Tiengen is located in Waldshut, Germany within 47° 37' 23.16" N 8° 12' 51.84" E (47.6231, 8.2144) coordinates. The local time in Waldshut-Tiengen is 22:08 (12.12.2025)
The calculated flying distance from Waldshut-Tiengen to Waldshut-Tiengen is 4,201.10 miles which is equal to 6,761.01 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Waldshut-Tiengen, Waldshut, Germany