Distance from Petersburg to Zell am See
The shortest distance (air line) between Petersburg and Zell am See is 4,402.64 mi (7,085.37 km).
How far is Petersburg from Zell am See
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 14:49 (09.02.2025)
Zell am See is located in Pinzgau-Pongau, Austria within 47° 19' 23.88" N 12° 47' 53.16" E (47.3233, 12.7981) coordinates. The local time in Zell am See is 20:49 (09.02.2025)
The calculated flying distance from Zell am See to Zell am See is 4,402.64 miles which is equal to 7,085.37 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
Zell am See, Pinzgau-Pongau, Austria