Distance from Petersburg to s-Heerenberg
The shortest distance (air line) between Petersburg and s-Heerenberg is 4,006.25 mi (6,447.43 km).
How far is Petersburg from s-Heerenberg
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 08:29 (01.03.2025)
s-Heerenberg is located in Achterhoek, Netherlands within 51° 52' 35.04" N 6° 14' 44.88" E (51.8764, 6.2458) coordinates. The local time in s-Heerenberg is 14:29 (01.03.2025)
The calculated flying distance from s-Heerenberg to s-Heerenberg is 4,006.25 miles which is equal to 6,447.43 km.
Petersburg, Virginia, United States
Related Distances from Petersburg
s-Heerenberg, Achterhoek, Netherlands