Distance from Ponte de Sor to Austintown
The shortest distance (air line) between Ponte de Sor and Austintown is 3,724.17 mi (5,993.46 km).
How far is Ponte de Sor from Austintown
Ponte de Sor is located in Alto Alentejo, Portugal within 39° 15' 0" N -9° 58' 59.88" W (39.2500, -8.0167) coordinates. The local time in Ponte de Sor is 22:02 (02.03.2025)
Austintown is located in Ohio, United States within 41° 5' 35.52" N -81° 15' 34.2" W (41.0932, -80.7405) coordinates. The local time in Austintown is 17:02 (02.03.2025)
The calculated flying distance from Austintown to Austintown is 3,724.17 miles which is equal to 5,993.46 km.
Ponte de Sor, Alto Alentejo, Portugal
Related Distances from Ponte de Sor
Austintown, Ohio, United States