Distance from Poughkeepsie to Aleksandrow Kujawski
The shortest distance (air line) between Poughkeepsie and Aleksandrow Kujawski is 4,100.64 mi (6,599.34 km).
How far is Poughkeepsie from Aleksandrow Kujawski
Poughkeepsie is located in New York, United States within 41° 41' 42" N -74° 4' 44.04" W (41.6950, -73.9211) coordinates. The local time in Poughkeepsie is 19:03 (16.05.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 01:03 (17.05.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 4,100.64 miles which is equal to 6,599.34 km.
Poughkeepsie, New York, United States
Related Distances from Poughkeepsie
Aleksandrow Kujawski, Włocławski, Poland