Distance from Poughkeepsie to Bad Sassendorf
The shortest distance (air line) between Poughkeepsie and Bad Sassendorf is 3,744.49 mi (6,026.17 km).
How far is Poughkeepsie from Bad Sassendorf
Poughkeepsie is located in New York, United States within 41° 41' 42" N -74° 4' 44.04" W (41.6950, -73.9211) coordinates. The local time in Poughkeepsie is 01:47 (28.04.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 07:47 (28.04.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 3,744.49 miles which is equal to 6,026.17 km.
Poughkeepsie, New York, United States
Related Distances from Poughkeepsie
Bad Sassendorf, Soest, Germany