Distance from Poughkeepsie to Waldshut-Tiengen
The shortest distance (air line) between Poughkeepsie and Waldshut-Tiengen is 3,864.23 mi (6,218.87 km).
How far is Poughkeepsie from Waldshut-Tiengen
Poughkeepsie is located in New York, United States within 41° 41' 42" N -74° 4' 44.04" W (41.6950, -73.9211) coordinates. The local time in Poughkeepsie is 22:36 (03.05.2025)
Waldshut-Tiengen is located in Waldshut, Germany within 47° 37' 23.16" N 8° 12' 51.84" E (47.6231, 8.2144) coordinates. The local time in Waldshut-Tiengen is 04:36 (04.05.2025)
The calculated flying distance from Waldshut-Tiengen to Waldshut-Tiengen is 3,864.23 miles which is equal to 6,218.87 km.
Poughkeepsie, New York, United States
Related Distances from Poughkeepsie
Waldshut-Tiengen, Waldshut, Germany