Distance from Povoa de Lanhoso to Aleksandrow Kujawski
The shortest distance (air line) between Povoa de Lanhoso and Aleksandrow Kujawski is 1,473.70 mi (2,371.70 km).
How far is Povoa de Lanhoso from Aleksandrow Kujawski
Povoa de Lanhoso is located in Ave, Portugal within 41° 34' 0.12" N -9° 43' 59.88" W (41.5667, -8.2667) coordinates. The local time in Povoa de Lanhoso is 04:49 (05.02.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 05:49 (05.02.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 1,473.70 miles which is equal to 2,371.70 km.
Povoa de Lanhoso, Ave, Portugal
Related Distances from Povoa de Lanhoso
Aleksandrow Kujawski, Włocławski, Poland