Distance from Prospect Heights to Aleksandrovac
The shortest distance (air line) between Prospect Heights and Aleksandrovac is 5,070.17 mi (8,159.65 km).
How far is Prospect Heights from Aleksandrovac
Prospect Heights is located in Illinois, United States within 42° 6' 14.04" N -88° 4' 23.88" W (42.1039, -87.9267) coordinates. The local time in Prospect Heights is 15:10 (21.05.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 22:10 (21.05.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 5,070.17 miles which is equal to 8,159.65 km.
Prospect Heights, Illinois, United States
Related Distances from Prospect Heights
Aleksandrovac, Rasinska oblast, Serbia