Distance from Prospect Heights to Sansepolcro
The shortest distance (air line) between Prospect Heights and Sansepolcro is 4,725.75 mi (7,605.36 km).
How far is Prospect Heights from Sansepolcro
Prospect Heights is located in Illinois, United States within 42° 6' 14.04" N -88° 4' 23.88" W (42.1039, -87.9267) coordinates. The local time in Prospect Heights is 03:30 (14.05.2025)
Sansepolcro is located in Arezzo, Italy within 43° 34' 32.16" N 12° 8' 38.04" E (43.5756, 12.1439) coordinates. The local time in Sansepolcro is 10:30 (14.05.2025)
The calculated flying distance from Sansepolcro to Sansepolcro is 4,725.75 miles which is equal to 7,605.36 km.
Prospect Heights, Illinois, United States