Distance from Prospect Heights to s-Heerenberg
The shortest distance (air line) between Prospect Heights and s-Heerenberg is 4,172.40 mi (6,714.83 km).
How far is Prospect Heights from s-Heerenberg
Prospect Heights is located in Illinois, United States within 42° 6' 14.04" N -88° 4' 23.88" W (42.1039, -87.9267) coordinates. The local time in Prospect Heights is 13:00 (17.05.2025)
s-Heerenberg is located in Achterhoek, Netherlands within 51° 52' 35.04" N 6° 14' 44.88" E (51.8764, 6.2458) coordinates. The local time in s-Heerenberg is 20:00 (17.05.2025)
The calculated flying distance from s-Heerenberg to s-Heerenberg is 4,172.40 miles which is equal to 6,714.83 km.
Prospect Heights, Illinois, United States
Related Distances from Prospect Heights
s-Heerenberg, Achterhoek, Netherlands