Distance from Providence to Sveti Ivan Zelina
The shortest distance (air line) between Providence and Sveti Ivan Zelina is 4,143.37 mi (6,668.11 km).
How far is Providence from Sveti Ivan Zelina
Providence is located in Rhode Island, United States within 41° 49' 22.8" N -72° 34' 52.68" W (41.8230, -71.4187) coordinates. The local time in Providence is 23:05 (24.02.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 05:05 (25.02.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 4,143.37 miles which is equal to 6,668.11 km.
Providence, Rhode Island, United States
Related Distances from Providence
Sveti Ivan Zelina, Zagrebačka županija, Croatia