Distance from Raamsdonksveer to Oxon Hill
The shortest distance (air line) between Raamsdonksveer and Oxon Hill is 3,864.86 mi (6,219.89 km).
How far is Raamsdonksveer from Oxon Hill
Raamsdonksveer is located in West-Noord-Brabant, Netherlands within 51° 40' 59.88" N 4° 52' 0.12" E (51.6833, 4.8667) coordinates. The local time in Raamsdonksveer is 09:17 (06.12.2025)
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 03:17 (06.12.2025)
The calculated flying distance from Oxon Hill to Oxon Hill is 3,864.86 miles which is equal to 6,219.89 km.
Raamsdonksveer, West-Noord-Brabant, Netherlands
Related Distances from Raamsdonksveer
Oxon Hill, Maryland, United States