Distance from Raamsdonksveer to Palmetto Bay
The shortest distance (air line) between Raamsdonksveer and Palmetto Bay is 4,648.84 mi (7,481.59 km).
How far is Raamsdonksveer from Palmetto Bay
Raamsdonksveer is located in West-Noord-Brabant, Netherlands within 51° 40' 59.88" N 4° 52' 0.12" E (51.6833, 4.8667) coordinates. The local time in Raamsdonksveer is 09:23 (06.12.2025)
Palmetto Bay is located in Florida, United States within 25° 37' 18.84" N -81° 40' 40.44" W (25.6219, -80.3221) coordinates. The local time in Palmetto Bay is 03:23 (06.12.2025)
The calculated flying distance from Palmetto Bay to Palmetto Bay is 4,648.84 miles which is equal to 7,481.59 km.
Raamsdonksveer, West-Noord-Brabant, Netherlands
Related Distances from Raamsdonksveer
Palmetto Bay, Florida, United States