Distance from Radviliskis to Jefferson Valley-Yorktown
The shortest distance (air line) between Radviliskis and Jefferson Valley-Yorktown is 4,181.81 mi (6,729.97 km).
How far is Radviliskis from Jefferson Valley-Yorktown
Radviliskis is located in Šiaulių apskritis, Lithuania within 55° 47' 60" N 23° 33' 0" E (55.8000, 23.5500) coordinates. The local time in Radviliskis is 19:26 (07.10.2025)
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 12:26 (07.10.2025)
The calculated flying distance from Jefferson Valley-Yorktown to Jefferson Valley-Yorktown is 4,181.81 miles which is equal to 6,729.97 km.
Radviliskis, Šiaulių apskritis, Lithuania
Related Distances from Radviliskis
Jefferson Valley-Yorktown, New York, United States