Distance from Ramnicu Valcea to Jefferson Valley-Yorktown
The shortest distance (air line) between Ramnicu Valcea and Jefferson Valley-Yorktown is 4,622.42 mi (7,439.07 km).
How far is Ramnicu Valcea from Jefferson Valley-Yorktown
Ramnicu Valcea is located in Vâlcea, Romania within 45° 6' 16.92" N 24° 22' 32.16" E (45.1047, 24.3756) coordinates. The local time in Ramnicu Valcea is 18:54 (27.12.2025)
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 11:54 (27.12.2025)
The calculated flying distance from Jefferson Valley-Yorktown to Jefferson Valley-Yorktown is 4,622.42 miles which is equal to 7,439.07 km.
Ramnicu Valcea, Vâlcea, Romania
Related Distances from Ramnicu Valcea
Jefferson Valley-Yorktown, New York, United States