Distance from Rancho Cucamonga to Saint-Genis-Pouilly
The shortest distance (air line) between Rancho Cucamonga and Saint-Genis-Pouilly is 5,867.70 mi (9,443.16 km).
How far is Rancho Cucamonga from Saint-Genis-Pouilly
Rancho Cucamonga is located in California, United States within 34° 7' 28.92" N -118° 25' 59.88" W (34.1247, -117.5667) coordinates. The local time in Rancho Cucamonga is 10:13 (28.02.2025)
Saint-Genis-Pouilly is located in Ain, France within 46° 14' 35.88" N 6° 1' 17.04" E (46.2433, 6.0214) coordinates. The local time in Saint-Genis-Pouilly is 19:13 (28.02.2025)
The calculated flying distance from Saint-Genis-Pouilly to Saint-Genis-Pouilly is 5,867.70 miles which is equal to 9,443.16 km.
Rancho Cucamonga, California, United States
Related Distances from Rancho Cucamonga
Saint-Genis-Pouilly, Ain, France