Distance from Reeuwijk to Alexandroupoli
The shortest distance (air line) between Reeuwijk and Alexandroupoli is 1,261.46 mi (2,030.12 km).
How far is Reeuwijk from Alexandroupoli
Reeuwijk is located in Oost-Zuid-Holland, Netherlands within 52° 2' 60" N 4° 43' 48" E (52.0500, 4.7300) coordinates. The local time in Reeuwijk is 11:09 (23.05.2025)
Alexandroupoli is located in Evros, Greece within 40° 51' 0" N 25° 52' 0.12" E (40.8500, 25.8667) coordinates. The local time in Alexandroupoli is 12:09 (23.05.2025)
The calculated flying distance from Alexandroupoli to Alexandroupoli is 1,261.46 miles which is equal to 2,030.12 km.
Reeuwijk, Oost-Zuid-Holland, Netherlands