Distance from Reeuwijk to Jefferson
The shortest distance (air line) between Reeuwijk and Jefferson is 4,338.02 mi (6,981.37 km).
How far is Reeuwijk from Jefferson
Reeuwijk is located in Oost-Zuid-Holland, Netherlands within 52° 2' 60" N 4° 43' 48" E (52.0500, 4.7300) coordinates. The local time in Reeuwijk is 15:27 (10.12.2025)
Jefferson is located in Georgia, United States within 34° 8' 14.28" N -84° 23' 52.44" W (34.1373, -83.6021) coordinates. The local time in Jefferson is 09:27 (10.12.2025)
The calculated flying distance from Jefferson to Jefferson is 4,338.02 miles which is equal to 6,981.37 km.
Reeuwijk, Oost-Zuid-Holland, Netherlands
Related Distances from Reeuwijk
Jefferson, Georgia, United States