Distance from Reeuwijk to Oxon Hill
The shortest distance (air line) between Reeuwijk and Oxon Hill is 3,850.26 mi (6,196.40 km).
How far is Reeuwijk from Oxon Hill
Reeuwijk is located in Oost-Zuid-Holland, Netherlands within 52° 2' 60" N 4° 43' 48" E (52.0500, 4.7300) coordinates. The local time in Reeuwijk is 17:38 (17.12.2025)
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 11:38 (17.12.2025)
The calculated flying distance from Oxon Hill to Oxon Hill is 3,850.26 miles which is equal to 6,196.40 km.
Reeuwijk, Oost-Zuid-Holland, Netherlands
Related Distances from Reeuwijk
Oxon Hill, Maryland, United States