Distance from Reeuwijk to Secaucus
The shortest distance (air line) between Reeuwijk and Secaucus is 3,643.47 mi (5,863.59 km).
How far is Reeuwijk from Secaucus
Reeuwijk is located in Oost-Zuid-Holland, Netherlands within 52° 2' 60" N 4° 43' 48" E (52.0500, 4.7300) coordinates. The local time in Reeuwijk is 12:44 (19.12.2025)
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 06:44 (19.12.2025)
The calculated flying distance from Secaucus to Secaucus is 3,643.47 miles which is equal to 5,863.59 km.
Reeuwijk, Oost-Zuid-Holland, Netherlands
Related Distances from Reeuwijk
Secaucus, New Jersey, United States