Distance from Reguengos de Monsaraz to Peekskill
The shortest distance (air line) between Reguengos de Monsaraz and Peekskill is 3,439.01 mi (5,534.55 km).
How far is Reguengos de Monsaraz from Peekskill
Reguengos de Monsaraz is located in Alentejo Central, Portugal within 38° 25' 0.12" N -8° 28' 0.12" W (38.4167, -7.5333) coordinates. The local time in Reguengos de Monsaraz is 15:14 (18.12.2025)
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 10:14 (18.12.2025)
The calculated flying distance from Peekskill to Peekskill is 3,439.01 miles which is equal to 5,534.55 km.
Reguengos de Monsaraz, Alentejo Central, Portugal
Related Distances from Reguengos de Monsaraz
Peekskill, New York, United States