Distance from Reguengos de Monsaraz to Petersburg
The shortest distance (air line) between Reguengos de Monsaraz and Petersburg is 3,717.18 mi (5,982.23 km).
How far is Reguengos de Monsaraz from Petersburg
Reguengos de Monsaraz is located in Alentejo Central, Portugal within 38° 25' 0.12" N -8° 28' 0.12" W (38.4167, -7.5333) coordinates. The local time in Reguengos de Monsaraz is 06:52 (09.01.2026)
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 01:52 (09.01.2026)
The calculated flying distance from Petersburg to Petersburg is 3,717.18 miles which is equal to 5,982.23 km.
Reguengos de Monsaraz, Alentejo Central, Portugal
Related Distances from Reguengos de Monsaraz
Petersburg, Virginia, United States