Distance from Reguengos de Monsaraz to Seven Hills
The shortest distance (air line) between Reguengos de Monsaraz and Seven Hills is 3,810.52 mi (6,132.43 km).
How far is Reguengos de Monsaraz from Seven Hills
Reguengos de Monsaraz is located in Alentejo Central, Portugal within 38° 25' 0.12" N -8° 28' 0.12" W (38.4167, -7.5333) coordinates. The local time in Reguengos de Monsaraz is 19:46 (06.01.2026)
Seven Hills is located in Ohio, United States within 41° 22' 49.08" N -82° 19' 35.04" W (41.3803, -81.6736) coordinates. The local time in Seven Hills is 14:46 (06.01.2026)
The calculated flying distance from Seven Hills to Seven Hills is 3,810.52 miles which is equal to 6,132.43 km.
Reguengos de Monsaraz, Alentejo Central, Portugal
Related Distances from Reguengos de Monsaraz
Seven Hills, Ohio, United States