Distance from Reynoldsburg to Sint-Katelijne-Waver
The shortest distance (air line) between Reynoldsburg and Sint-Katelijne-Waver is 4,044.09 mi (6,508.33 km).
How far is Reynoldsburg from Sint-Katelijne-Waver
Reynoldsburg is located in Ohio, United States within 39° 57' 31.68" N -83° 12' 20.52" W (39.9588, -82.7943) coordinates. The local time in Reynoldsburg is 17:20 (24.02.2025)
Sint-Katelijne-Waver is located in Arr. Mechelen, Belgium within 51° 4' 0.12" N 4° 31' 59.88" E (51.0667, 4.5333) coordinates. The local time in Sint-Katelijne-Waver is 23:20 (24.02.2025)
The calculated flying distance from Sint-Katelijne-Waver to Sint-Katelijne-Waver is 4,044.09 miles which is equal to 6,508.33 km.
Reynoldsburg, Ohio, United States
Related Distances from Reynoldsburg
Sint-Katelijne-Waver, Arr. Mechelen, Belgium