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      Distance from Richardson to Saint-Andre-les-Vergers

      The shortest distance (air line) between Richardson and Saint-Andre-les-Vergers is 5,004.12 mi (8,053.35 km).

      How far is Richardson from Saint-Andre-les-Vergers

      Richardson is located in Texas, United States within 32° 58' 17.76" N -97° 17' 26.52" W (32.9716, -96.7093) coordinates. The local time in Richardson is 12:43 (05.05.2025)

      Saint-Andre-les-Vergers is located in Aube, France within 48° 16' 46.92" N 4° 3' 14.04" E (48.2797, 4.0539) coordinates. The local time in Saint-Andre-les-Vergers is 19:43 (05.05.2025)

      The calculated flying distance from Saint-Andre-les-Vergers to Saint-Andre-les-Vergers is 5,004.12 miles which is equal to 8,053.35 km.

      Richardson, Texas, United States

      Related Distances from Richardson

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      Richardson to Washington (District of Columbia)1,172.50 mi (1,886.95 km)
      Richardson to San Diego (California)1,182.35 mi (1,902.81 km)
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      Richardson to Brooklyn (New York)1,361.12 mi (2,190.51 km)
      Richardson to New York (New York)1,363.19 mi (2,193.85 km)
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      Richardson to San Francisco (California)1,482.21 mi (2,385.38 km)
      Richardson to Boston (Massachusetts)1,535.51 mi (2,471.16 km)
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      Saint-Andre-les-Vergers, Aube, France

      Related Distances to Saint-Andre-les-Vergers