Distance from Ridge to Dimitrovgrad
The shortest distance (air line) between Ridge and Dimitrovgrad is 4,622.99 mi (7,439.98 km).
How far is Ridge from Dimitrovgrad
Ridge is located in New York, United States within 40° 54' 24.48" N -73° 7' 6.24" W (40.9068, -72.8816) coordinates. The local time in Ridge is 05:01 (25.04.2025)
Dimitrovgrad is located in Pirotska oblast, Serbia within 43° 1' 0.12" N 22° 46' 59.88" E (43.0167, 22.7833) coordinates. The local time in Dimitrovgrad is 11:01 (25.04.2025)
The calculated flying distance from Dimitrovgrad to Dimitrovgrad is 4,622.99 miles which is equal to 7,439.98 km.
Ridge, New York, United States
Related Distances from Ridge
Dimitrovgrad, Pirotska oblast, Serbia