Distance from Ridgeland to Aleksandrow Kujawski
The shortest distance (air line) between Ridgeland and Aleksandrow Kujawski is 5,164.92 mi (8,312.13 km).
How far is Ridgeland from Aleksandrow Kujawski
Ridgeland is located in Mississippi, United States within 32° 25' 24.96" N -91° 51' 6.84" W (32.4236, -90.1481) coordinates. The local time in Ridgeland is 17:22 (03.04.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 00:22 (04.04.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 5,164.92 miles which is equal to 8,312.13 km.
Ridgeland, Mississippi, United States
Related Distances from Ridgeland
Aleksandrow Kujawski, Włocławski, Poland