Distance from Ridgeland to Dimitrovgrad
The shortest distance (air line) between Ridgeland and Dimitrovgrad is 5,720.99 mi (9,207.05 km).
How far is Ridgeland from Dimitrovgrad
Ridgeland is located in Mississippi, United States within 32° 25' 24.96" N -91° 51' 6.84" W (32.4236, -90.1481) coordinates. The local time in Ridgeland is 21:56 (24.02.2025)
Dimitrovgrad is located in Pirotska oblast, Serbia within 43° 1' 0.12" N 22° 46' 59.88" E (43.0167, 22.7833) coordinates. The local time in Dimitrovgrad is 04:56 (25.02.2025)
The calculated flying distance from Dimitrovgrad to Dimitrovgrad is 5,720.99 miles which is equal to 9,207.05 km.
Ridgeland, Mississippi, United States
Related Distances from Ridgeland
Dimitrovgrad, Pirotska oblast, Serbia