Distance from Roanoke to Bad Segeberg
The shortest distance (air line) between Roanoke and Bad Segeberg is 4,203.65 mi (6,765.12 km).
How far is Roanoke from Bad Segeberg
Roanoke is located in Virginia, United States within 37° 16' 42.6" N -80° 2' 30.84" W (37.2785, -79.9581) coordinates. The local time in Roanoke is 08:09 (08.05.2025)
Bad Segeberg is located in Segeberg, Germany within 53° 55' 0.12" N 10° 19' 0.12" E (53.9167, 10.3167) coordinates. The local time in Bad Segeberg is 14:09 (08.05.2025)
The calculated flying distance from Bad Segeberg to Bad Segeberg is 4,203.65 miles which is equal to 6,765.12 km.
Roanoke, Virginia, United States
Related Distances from Roanoke
Bad Segeberg, Segeberg, Germany