Distance from Robinson to Aleksandrow Lodzki
The shortest distance (air line) between Robinson and Aleksandrow Lodzki is 5,520.16 mi (8,883.84 km).
How far is Robinson from Aleksandrow Lodzki
Robinson is located in Texas, United States within 31° 27' 0.36" N -98° 52' 47.64" W (31.4501, -97.1201) coordinates. The local time in Robinson is 09:37 (01.06.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 16:37 (01.06.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 5,520.16 miles which is equal to 8,883.84 km.
Robinson, Texas, United States
Related Distances from Robinson
Aleksandrow Lodzki, Łódzki, Poland