Distance from Robstown to Aleksandrow Lodzki
The shortest distance (air line) between Robstown and Aleksandrow Lodzki is 5,748.13 mi (9,250.72 km).
How far is Robstown from Aleksandrow Lodzki
Robstown is located in Texas, United States within 27° 47' 38.4" N -98° 19' 50.88" W (27.7940, -97.6692) coordinates. The local time in Robstown is 09:32 (18.05.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 16:32 (18.05.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 5,748.13 miles which is equal to 9,250.72 km.
Robstown, Texas, United States
Related Distances from Robstown
Aleksandrow Lodzki, Łódzki, Poland