Distance from Robstown to Begijnendijk
The shortest distance (air line) between Robstown and Begijnendijk is 5,248.89 mi (8,447.27 km).
How far is Robstown from Begijnendijk
Robstown is located in Texas, United States within 27° 47' 38.4" N -98° 19' 50.88" W (27.7940, -97.6692) coordinates. The local time in Robstown is 19:01 (06.04.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 02:01 (07.04.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 5,248.89 miles which is equal to 8,447.27 km.
Robstown, Texas, United States
Related Distances from Robstown
Begijnendijk, Arr. Leuven, Belgium