Distance from Rosenberg to Boortmeerbeek
The shortest distance (air line) between Rosenberg and Boortmeerbeek is 5,076.90 mi (8,170.48 km).
How far is Rosenberg from Boortmeerbeek
Rosenberg is located in Texas, United States within 29° 32' 44.16" N -96° 10' 39.72" W (29.5456, -95.8223) coordinates. The local time in Rosenberg is 07:01 (24.02.2025)
Boortmeerbeek is located in Arr. Leuven, Belgium within 50° 58' 59.88" N 4° 34' 0.12" E (50.9833, 4.5667) coordinates. The local time in Boortmeerbeek is 14:01 (24.02.2025)
The calculated flying distance from Boortmeerbeek to Boortmeerbeek is 5,076.90 miles which is equal to 8,170.48 km.
Rosenberg, Texas, United States
Related Distances from Rosenberg
Boortmeerbeek, Arr. Leuven, Belgium