Distance from Rosenberg to Mercato San Severino
The shortest distance (air line) between Rosenberg and Mercato San Severino is 5,859.82 mi (9,430.46 km).
How far is Rosenberg from Mercato San Severino
Rosenberg is located in Texas, United States within 29° 32' 44.16" N -96° 10' 39.72" W (29.5456, -95.8223) coordinates. The local time in Rosenberg is 15:11 (12.12.2025)
Mercato San Severino is located in Salerno, Italy within 40° 46' 59.88" N 14° 46' 0.12" E (40.7833, 14.7667) coordinates. The local time in Mercato San Severino is 22:11 (12.12.2025)
The calculated flying distance from Mercato San Severino to Mercato San Severino is 5,859.82 miles which is equal to 9,430.46 km.
Rosenberg, Texas, United States
Related Distances from Rosenberg
Mercato San Severino, Salerno, Italy