Distance from Rosenberg to San Lazzaro di Savena
The shortest distance (air line) between Rosenberg and San Lazzaro di Savena is 5,575.86 mi (8,973.47 km).
How far is Rosenberg from San Lazzaro di Savena
Rosenberg is located in Texas, United States within 29° 32' 44.16" N -96° 10' 39.72" W (29.5456, -95.8223) coordinates. The local time in Rosenberg is 07:42 (17.12.2025)
San Lazzaro di Savena is located in Bologna, Italy within 44° 28' 17.76" N 11° 24' 17.64" E (44.4716, 11.4049) coordinates. The local time in San Lazzaro di Savena is 14:42 (17.12.2025)
The calculated flying distance from San Lazzaro di Savena to San Lazzaro di Savena is 5,575.86 miles which is equal to 8,973.47 km.
Rosenberg, Texas, United States
Related Distances from Rosenberg
San Lazzaro di Savena, Bologna, Italy