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      Distance from Rosenberg to Sint-Pieters-Leeuw

      The shortest distance (air line) between Rosenberg and Sint-Pieters-Leeuw is 5,070.78 mi (8,160.63 km).

      How far is Rosenberg from Sint-Pieters-Leeuw

      Rosenberg is located in Texas, United States within 29° 32' 44.16" N -96° 10' 39.72" W (29.5456, -95.8223) coordinates. The local time in Rosenberg is 02:41 (25.02.2025)

      Sint-Pieters-Leeuw is located in Arr. Halle-Vilvoorde, Belgium within 50° 46' 59.88" N 4° 15' 0" E (50.7833, 4.2500) coordinates. The local time in Sint-Pieters-Leeuw is 09:41 (25.02.2025)

      The calculated flying distance from Sint-Pieters-Leeuw to Sint-Pieters-Leeuw is 5,070.78 miles which is equal to 8,160.63 km.

      Rosenberg, Texas, United States

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      Rosenberg to Queens (New York)1,459.07 mi (2,348.14 km)
      Rosenberg to San Francisco (California)1,626.01 mi (2,616.81 km)
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      Sint-Pieters-Leeuw, Arr. Halle-Vilvoorde, Belgium

      Related Distances to Sint-Pieters-Leeuw