Distance from Rotenburg an der Fulda to Peekskill
The shortest distance (air line) between Rotenburg an der Fulda and Peekskill is 3,841.09 mi (6,181.63 km).
How far is Rotenburg an der Fulda from Peekskill
Rotenburg an der Fulda is located in Hersfeld-Rotenburg, Germany within 50° 59' 45.96" N 9° 43' 40.08" E (50.9961, 9.7278) coordinates. The local time in Rotenburg an der Fulda is 09:34 (28.12.2025)
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 03:34 (28.12.2025)
The calculated flying distance from Peekskill to Peekskill is 3,841.09 miles which is equal to 6,181.63 km.
Rotenburg an der Fulda, Hersfeld-Rotenburg, Germany
Related Distances from Rotenburg an der Fulda
Peekskill, New York, United States