Distance from Rothenburg ob der Tauber to Bad Sassendorf
The shortest distance (air line) between Rothenburg ob der Tauber and Bad Sassendorf is 175.94 mi (283.15 km).
How far is Rothenburg ob der Tauber from Bad Sassendorf
Rothenburg ob der Tauber is located in Ansbach; Landkreis, Germany within 49° 22' 59.88" N 10° 10' 59.88" E (49.3833, 10.1833) coordinates. The local time in Rothenburg ob der Tauber is 05:42 (19.11.2024)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 05:42 (19.11.2024)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 175.94 miles which is equal to 283.15 km.
Rothenburg ob der Tauber, Ansbach; Landkreis, Germany
Related Distances from Rothenburg ob der Tauber
Bad Sassendorf, Soest, Germany