Distance from Ruskin to Agia Varvara
The shortest distance (air line) between Ruskin and Agia Varvara is 5,849.24 mi (9,413.44 km).
How far is Ruskin from Agia Varvara
Ruskin is located in Florida, United States within 27° 42' 23.4" N -83° 34' 44.76" W (27.7065, -82.4209) coordinates. The local time in Ruskin is 13:49 (11.03.2025)
Agia Varvara is located in Dytikos Tomeas Athinon, Greece within 38° 0' 0" N 23° 38' 60" E (38.0000, 23.6500) coordinates. The local time in Agia Varvara is 20:49 (11.03.2025)
The calculated flying distance from Agia Varvara to Agia Varvara is 5,849.24 miles which is equal to 9,413.44 km.
Ruskin, Florida, United States
Related Distances from Ruskin
Agia Varvara, Dytikos Tomeas Athinon, Greece