Distance from Ruskin to Boortmeerbeek
The shortest distance (air line) between Ruskin and Boortmeerbeek is 4,630.10 mi (7,451.43 km).
How far is Ruskin from Boortmeerbeek
Ruskin is located in Florida, United States within 27° 42' 23.4" N -83° 34' 44.76" W (27.7065, -82.4209) coordinates. The local time in Ruskin is 09:32 (24.02.2025)
Boortmeerbeek is located in Arr. Leuven, Belgium within 50° 58' 59.88" N 4° 34' 0.12" E (50.9833, 4.5667) coordinates. The local time in Boortmeerbeek is 15:32 (24.02.2025)
The calculated flying distance from Boortmeerbeek to Boortmeerbeek is 4,630.10 miles which is equal to 7,451.43 km.
Ruskin, Florida, United States
Related Distances from Ruskin
Boortmeerbeek, Arr. Leuven, Belgium