Distance from Ruskin to Borgerhout
The shortest distance (air line) between Ruskin and Borgerhout is 4,620.47 mi (7,435.94 km).
How far is Ruskin from Borgerhout
Ruskin is located in Florida, United States within 27° 42' 23.4" N -83° 34' 44.76" W (27.7065, -82.4209) coordinates. The local time in Ruskin is 01:26 (13.06.2025)
Borgerhout is located in Arr. Antwerpen, Belgium within 51° 12' 42.12" N 4° 26' 26.52" E (51.2117, 4.4407) coordinates. The local time in Borgerhout is 07:26 (13.06.2025)
The calculated flying distance from Borgerhout to Borgerhout is 4,620.47 miles which is equal to 7,435.94 km.
Ruskin, Florida, United States
Related Distances from Ruskin
Borgerhout, Arr. Antwerpen, Belgium