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      Distance from Ruskin to Chateauneuf-les-Martigues

      The shortest distance (air line) between Ruskin and Chateauneuf-les-Martigues is 4,817.78 mi (7,753.46 km).

      How far is Ruskin from Chateauneuf-les-Martigues

      Ruskin is located in Florida, United States within 27° 42' 23.4" N -83° 34' 44.76" W (27.7065, -82.4209) coordinates. The local time in Ruskin is 07:11 (27.02.2025)

      Chateauneuf-les-Martigues is located in Bouches-du-Rhône, France within 43° 22' 59.16" N 5° 9' 51.12" E (43.3831, 5.1642) coordinates. The local time in Chateauneuf-les-Martigues is 13:11 (27.02.2025)

      The calculated flying distance from Chateauneuf-les-Martigues to Chateauneuf-les-Martigues is 4,817.78 miles which is equal to 7,753.46 km.

      Ruskin, Florida, United States

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      Chateauneuf-les-Martigues, Bouches-du-Rhône, France

      Related Distances to Chateauneuf-les-Martigues